(x^2-2x)^2-23(x^2-2x)+120=0

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Solution for (x^2-2x)^2-23(x^2-2x)+120=0 equation: 



(x^2-2x)^2-23(x^2-2x)+120=0

We multiply parentheses

-23x^2+(x^2-2x)^2+46x+120=0

We add all the numbers together, and all the variables

-23x^2+46x+(x^2-2x)^2+120=0

We move all terms containing x to the left, all other terms to the right

-23x^2+46x+(x^2-2x)^2=-120

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